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Radioactive Decay Calculator

Model exponential radioactive decay with N = N₀ e^(−λt) — enter the initial amount, decay constant λ and time to get the amount remaining, or solve for λ or time. Also shows the half-life and activity.

 

Formula

$$ N = N_0\,e^{-\lambda t} \qquad \lambda=\frac{\ln(N_0/N)}{t} \qquad t=\frac{\ln(N_0/N)}{\lambda} \qquad t_{1/2}=\frac{\ln 2}{\lambda} $$

Worked example

With N₀ = 1,000,000 nuclei and λ = 1.21×10⁻⁴ /yr (carbon-14), after 11,460 years, \( N = 10^{6} e^{-(1.21\times10^{-4})(11460)} \approx 250{,}000 \) — a quarter left, matching two half-lives (t½ = ln2/λ ≈ 5,730 yr).

How it works

Radioactive nuclei decay at a rate proportional to how many remain, giving exponential decay N = N₀ e^(−λt). The decay constant λ is the probability per unit time that a given nucleus decays.

λ relates directly to half-life by t½ = ln2/λ ≈ 0.693/λ. The activity (decays per second, in becquerel) is A = λN. Keep λ and t in matching time units; the calculator reports the equivalent half-life alongside the result.

Frequently asked questions

What is the radioactive decay formula?

N = N₀ e^(−λt): the amount remaining equals the initial amount times e to the power minus the decay constant times time.

What is the decay constant λ?

λ is the probability per unit time that a nucleus decays. It relates to half-life by λ = ln2 / t½ and to activity by A = λN.

How is decay constant related to half-life?

They are inversely related: t½ = ln2/λ ≈ 0.693/λ. A larger decay constant means a shorter half-life.

What is activity measured in?

The becquerel (Bq), one decay per second. Activity A = λN falls off exponentially just like the number of nuclei.

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