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Specific Heat Calculator

Find the heat energy needed to change a substance's temperature with Q = m c ΔT — or solve for mass, specific heat capacity or temperature change.

 

Formula

$$ Q = m\,c\,\Delta T \qquad m=\frac{Q}{c\,\Delta T} \qquad c=\frac{Q}{m\,\Delta T} \qquad \Delta T=\frac{Q}{m\,c} $$

Worked example

Heating 0.5 kg of water (c = 4186 J/kg·K) by 40 °C needs \( Q = (0.5)(4186)(40) \approx 83{,}700\ \text{J} \) — about 83.7 kJ, or the energy in roughly 20 kcal.

How it works

Specific heat capacity c is the energy needed to raise 1 kg of a substance by 1 kelvin. The heat to change a mass m by ΔT is Q = m c ΔT, with Q in joules.

Water has an unusually high specific heat (4186 J/kg·K), which is why oceans moderate climate and why it is an effective coolant. A temperature change in kelvin equals the same change in °C, so ΔT can be entered in either.

Frequently asked questions

What is the formula for specific heat?

The heat energy is Q = m c ΔT — mass times specific heat capacity times temperature change. Rearranged, c = Q / (m ΔT).

What is the specific heat of water?

About 4186 J/(kg·K) (or 4.186 J/g·°C, or 1 cal/g·°C) for liquid water — one of the highest of common substances.

Do I use kelvin or Celsius for ΔT?

Either works, because a temperature difference is numerically identical in kelvin and Celsius. Only use absolute kelvin when a formula needs the temperature itself, not a change.

What are the units of specific heat capacity?

Joules per kilogram per kelvin, J/(kg·K), equivalent to J/(kg·°C).

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